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He-Man and his comrades are heading towards the battlefield, in a planned face-off against Skeletor and his goons. When they confronted their enemies, they had found an unfortunate situation: Skeletor's forces were on higher ground than them (on a mountain), leading to a widely unfair advantage. He-Man thought out the situation while his comrades kept the enemy busy, and had decided to calculate whether or not throwing a projectile at Skeletor was practical or not. He had estimated about 200 feet of distance between them (from He-Man to the base of the mountain), and a 70° angle of elevation to Skeletor. How far would his throw have to be, in order for his projectile to (diagonally and in a straight line) reach Skeletor?
S(keletor)
|\
| \
| \ cos 70° = 200 ft.
| \ h
| \
| \ h x cos 70° = 200 ft.
| \
| \ 200 ft.
| \ --------- = 584.76 ft.
| \ cos 70°
| 70° \ H(e-Man)
200 ft.
Seeing as how a throw that would have to travel 584.76 ft. was impractical, He-Man had simply decided to find a nearby mountain with a higher elevation, in order to reduce the required power in that throw. After a short while, He-Man finds a fitting spot upon a mountain, measuring 600 ft. in height. If Skeletor's elevation was 549.5 ft., and the angle of depression was 10°, then what would be the distance that He-Man's new-and-improved throw have to be?